From Problem 2.13 we know that,
From (1) and (2) we have,
In (4), h-h0 represents height above sea level and P0 the atmospheric pressure at sea level and T I am guessing is assumed to be 273K.
So at a height of 5 Km above sea level we have,
Similarly at a height of 5 Km below sea level we have,
though 5 km is less shouln't we consider the change in gravity and right g as a function of h and then integrate from the basic.
ReplyDeleteNo, that’s silly. 5km is nothing compared to the radius of Earth. Gravity 5km up will be (6371/6376)^2 = 99.8% of surface strength.
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